Question

3. Find the remainder using remainder theorem, when x³ – ax²– 5x + 2a is divided by x-a​

Answer 1

p(x) = x³ – ax²– 5x + 2a

Divisor = x - a

x - a = 0

x = a

Substituting x in p(x)

p(x) = x³ – ax²– 5x + 2a

= a³ – a(a)²– 5(a) + 2a

= a³ – a³ – 5a + 2a

= -5a + 2a

= -3a

Remainder = -3a

Answer 2

Answer:

According to remainder theorem if p(x) divided by x-a then remainder is equal to p(a).

Put value of x is equal to a.

So remainder is equal to:

p(a) = a^3 - a*a^2 + 6 - a

p(a) = a^3 - a^3 + 6 - a

p(a) = 6 - a.