Question

3)Find the simple interest on Rs 1 po
1000 for 2 years at 8% per
annum
*​

Answer 1

Given :-

• Principal ( P ) = Rs 1,000  
• Rate of interest ( r ) R = 8 %  
• Time ( T ) = 2 years  

To Find :-

• Calculate the simple interest ( SI )  

Solution :-

~Here, we’re given the principal , rate of interest, time and we need to find the simple interest. We can easily find the simple interest by putting the values in the formula.  

____________

As we know that ,

$\boxed{\sf{ \maltese \;\; SI = \dfrac{ P \times r \times T }{100}}}$

Finding the simple interest :-

$\sf \dashrightarrow SI = \dfrac{1,000 \times 8 \times 2 }{100}$

$\sf \dashrightarrow SI = 10 \times 8 \times 2$

$\boxed{\bf{ \bigstar \;\; Simple\;Interest = Rs. \; 160 }}$

____________

Hence,  

• The simple interest is of Rs. 160

Answer 2

ANSWER :

It is given to find the simple interest on Principal (P) = Rs. 1000, Time (T) = 2 years and Rate (R) = 8% per annum,

Follow the steps...

$\Rightarrow$ Simple Interest (S.I.) = $\frac{P × R × T}{100}$

$\Rightarrow$ S.I. = $\frac{1000 × 8 × 2}{100}$

$\Rightarrow$ S.I. = $\frac{10 \cancel 0 \cancel0 × 8 × 2}{1 \cancel 0 \cancel0}$

$\Rightarrow$ S.I. = 10 × 8 × 2 = 10 × 16

$\Rightarrow$ S.I. = 160

→ Thus, we can notice that the simple interest on Rs. 1000 for 2 years at the rate of 8% per annum must be Rs. 160.