3.
Find the smallest number by which 2560 must be multiplied so that the product a
perfect cube.
Answers
Answered by
1
Answer:
2^3×4^3×5
Step-by-step explanation:
2 ×2×4×4×4×2×5=2560
Answered by
0
Answer:
we try to find by prime factorisation
step by step explaination
\sqrt[3]{2560 }
3
2560
2560=
2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 52×2×2×2×2×2×2×2×2×5
clearly for making cube must be multiply by
5 \times 55×5
= 25=25
both side
2560 \times 25 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 52560×25=2×2×2×2×2×2×2×2×2×5×5×5
hence,
64060=2560 .
ans. = smallest number is 25
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