Question

3. Find the smallest number by which each of the following numbers must be divided to
obtain a perfect cube.
(i) 81
(ii) 128
(iii) 135
(iv) 192
(v) 704​

Answer 1

1) the smallest number by which 81 should be divided to make a perfect cube is 3: the prime factors 2 is not present as triples. Hence, we divide 128 by 2, so that the obtained number becomes a perfect cube.

2) smallest number by which 128 should be divided to make it a perfect cube is 2.: 27= (3 x 3 x 3)

3) the smallest number by which 135 should be divided to make it a perfect cube is 54: Here, the prime factors 3 is not present as triples

4) the smallest number by which 192 should be divided to make a perfect cube is 3: 192÷3=64=23×23=43 192 ÷ 3 = 64 = 2 3 × 2 3 = 4

5) we divide 704 by 11, so that the obtained number becomes a perfect cube. 704÷11=64=23×23=43 704 ÷ 11 = 64 = 2 3 × 2 3 = 4 3 is a perfect cube.

Threre ya go and pls mark me as the brainliest plsssss