Math, asked by prshu, 7 months ago

3) Find the smallest number which when diminished by 7 is divisible by 12, 16, 18, 21 and 28.​

Answers

Answered by bhupindersingh07
1

Answer:

First find the smallest number divisible by 12,16,18,21 and 28. It is the LCM of these numbers. So the number will be 1008+7 = 1015.

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