Question

3) Find the squares of the following numbers by
any algebrical identity method a)27​

Answer 1

Answer:

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Answer 2

Answer:

19683

Step-by-step explanation:

$27^{3}$

(30-3)^3

a= 30, b=3    , therefore $(a-b)^{3}$ = a3 - b3 -3ab(a-b)

$30^{3}$ - $3^{3}$- 3x 30x3(30-3)

27000-27-270(30-3)

19683