Question

3. Find the sum of 100 terms of the AP 0.6,0.61,0.62,0.63,.... .​

Answer 1

Answer:

109.5

Step-by-step explanation:

1st term , a = 0.6

common difference, d = 0.01

no. of terms, n = 100

$sum \: of \: n \: terms = \frac{n}{2} \times (2a + (n - 1)d)$

S100 = 50(1.2 + 99×0.01)

= 50(1.2+0.99)

= 50(2.19)

=109.5