Math, asked by DerinSamuel467, 9 months ago

3. Find the sum of 3 + 11 + 19 + - - - -+ 803.
4. Find the tenth term of the sequence √2, √8, √18, ……
{ Hint : given terms are √2, 2√2, 3√2…….}
5. How many terms are there in the A.P 3,7,11……………407

pls ans for next question will be 20 pts

Answers

Answered by pyarip
2

Answer:

3.1/2(a+l)

1/2(3+803)

1/2×806

=403

4.d=1

a=

2 \sqrt[?]{?}

a10=square root 2+9

Answered by mhanifa
1

Answer:

3. 40703,

4. 10√2,

5. 102

Step-by-step explanation:

3. Sum of 3+11+19+...+803

This is AP, where

  • a=3,
  • d=11-3=8,
  • n=1+(803-3)/8= 101
  • Sₙ=1/2*101*(3+803)= 40703
  • Sₙ=40703

====

4. Find the tenth term of the sequence √2, √8, √18, …

  • 1√2, 2√2, 3√2,..., 10√2
  • 10th term = 10√2

===

5. How many terms are there in the A.P 3,7,11……………407

  • d= 7-3=4
  • n=1+(407-3)/4= 102

Number of terms is 102

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