3. Find the sum of each arithmetic series
(i) 38 + 35 + 32 +........+2
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First we have to know that how many terms are there in the above series.
a = 38 d = t₂ - t₁ L = 2
d = 35-38
= -3
n = [(L-a)/d] + 1
= [(2-38)/(-3)] + 1
= [(-36)/(-3)] + 1
= 12 + 1
n = 13
S n = (n/2) (a+L)
= (13/2) (38 + 2)
= (13/2) (40)
= (13) (20)
= 260
a = 38 d = t₂ - t₁ L = 2
d = 35-38
= -3
n = [(L-a)/d] + 1
= [(2-38)/(-3)] + 1
= [(-36)/(-3)] + 1
= 12 + 1
n = 13
S n = (n/2) (a+L)
= (13/2) (38 + 2)
= (13/2) (40)
= (13) (20)
= 260
Answered by
2
Hope it is helpful ✌
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