Question

3. Find the sum of even positive integers between 1 and 200.​

Answer 1

Answer:

total even nos.bw 1 and 200

200/2is 100

now excluding last digit 200 then

total terms :

100-1 =99

sum method=

n/2(2@+(n-1)d)

a=2. d=2

then

99/2(2*2+98*2)

=99/2(4+196)

=99*100=9900

I hope it was helpful!

thank you!