3. Find the sum of measures of all interior angles of a polygon with number of sides
(1) 8
(ii) 12
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Step-by-step explanation:
The sum of the interior angles of a polygon is four times the sum of its exterior angles.
The sum of the exterior angles of a polygon is always equal to 360
o
.
The sum of the interior angles of polygon = 180(n−2)
=> 180(n−2)=4×360
=> n−2=8
=> n=10
Number of sides in the polygon = 10
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