Math, asked by mohdmulla7869, 1 month ago

3. Find the value of k for which the system of equations 6x + ky = 5 and 3x + y = 1 has no solution .​

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Answered by ishaandraws
0

Answer:

The given system of equations: 3x - y - 5 = 0 ….(i) And, 6x - 2y + k = 0 ….(ii) These equations are of the following form: a1x+b1y+c1 = 0, a2x+b2y+c2 = 0 where, a1 = 3, b1= -1, c1 = -5 and a2 = 6, b2 = -2, c2 = k In order that the given system has no solution, we must have: Hence, equations (i) and (ii) will have no solution if k ≠ -10.Read more on Sarthaks.com - htt/find-the-value-of-k-for-which-the-system-of-equations-3x-y-5-6x-2y-k-has-no-solution

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