Question

3.
Find the value of k, if x-1 is a factor of p(x)
if p(x)=2x^2+Kx+2^1/2​

Answer 1

(x-1) is a factor of the given polynomial.

So x = 1 is a zero of the polynomial

p(1) = 2*1² + k*1 + √2 = 0

        2 + k +√2 = 0

        k = -(2+√2)

Answer 2

Answer:

k=-√8

Step-by-step explanation:

Given

f(x)=x-1

p(x)=2x^2+kx+2^1/2

let,

f(x)=0

x-1=0

x=0+1

x =1

substitute x=1 in p(x)

such that,

2x^2+kx+2^1/2=0

2(1)^2+k(1)+2^1/2=0

2(1)+k+2^1/2=0

2+k+2^1/2=0

k=-2 •√-2

k=√-4•-2

k=-√8