Question

3. Find the value of k or C for which the following systems of equations be in consistent or no solution.

(ii) Cx + 3y = 3
kx + 8y + 3k=0
12x + Cy = 6
​

Answer 1

Answer:

k=16&c=6

Step-by-step explanation:

since there is no solution

a1/a2=b1/B2

CX+3y=3&12x+CY=6.

c/12=3/c

c^2=12×3

c^2=36

→c=√36=6.

now,c/k=3/8

c=3k/8

6=3k/8

48=3k

→k=48/3=16