Question

3) Find the value of p when (x2+3x+p) is divisible by x-2.​

Answer 1

Answer:

-13

Step-by-step explanation:

x² +3x + p is divisible by (x-2)

meaning x-2 is a factor

from that, x-2=0

so x = 2

sub x=2 in the equation

(2)² + 3(2) + p = 0 (it's is equal to 0 because there is no remainder, since x= 2 is a factor.

4 + 6 + p =0

13 + p = 0

therefore, p = -13

Answer 2

${ \bf{ \huge{ \underline{Answer}}}}$

${ \rm{ \large{ { \longrightarrow - 10}}}}$

${ \bf{ \huge{ \underline{Solution}}}}$

${ \rm{ \large{the \: factor \: is \: \: x - 2 = 0 }}}$

${ \rm{ \large{ \implies x = 2}}}$

${ \rm{ \large{ {x}^{2} + 3x + p = 0}}}$

${ \rm{ \large{ \implies {2}^{2} + 3 \times 2 + p = 0 \: \: \: \: (x = 2)}}}$

${ \rm{ \large{ \implies 4 +6 + p = 0 }}}$

${ \rm{ \large{ \implies p = - 6 - 4 }}}$

${ \rm{ \large{ \implies p = - 10 }}}$

${ \rm{ \large{ \therefore \: The \: value \: of \: p = - 10 }}}$