Question

3)
Find the value of p when (x2+3x+p) is divisible by x-2.​

Answer 1

Answer:

the value of p =-10 in the equation x²+3x+p

Answer 2

$\sf \Large Solution!!$

If $\sf (x^{2}+3x+p)$ is divisible by $\sf (x-2)$, then the remainder will be zero.

$\sf \to x-2=0\\\to x=2$

$\sf \to f(x)=x^{2}+3x+p$

$\sf \to f(2)=(2)^{2}+3(2)+p$

$\sf \to 0=4+6+p$

$\sf \bigstar \blue{p=-10}$