Question

3. Find the value of P(x) =(x-1) (x+1)(x+2) at x=-1​

Answer 1

ans =0

P(x)=(x-1)(x+1)(x+2)

p(-1)=(-1-1)(-1+1)(-1+2)

=(-2)(0)(1)

=0

Answer 2

Question :-

Find the value of P ( x ) = ( x - 1 ) ( x + 1 ) ( x + 2 ) at x = - 1

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Solution :-

Given Information :-

• P ( x ) = ( x - 1 ) ( x + 1 ) ( x + 2 )
• x = - 1

Calculation :-

The given value of 'x' is - 1.

Substituting the values,

⇒ P ( - 1 ) = [ ( - 1 ) -1 ] [ ( - 1 ) + 1 ] [ ( - 1 ) + 2]

⇒ P ( - 1 ) = [ - 2 ] [ 0 ] [ 1 ]

⇒ P ( - 1 ) = 0

Answer :- P ( - 1 ) = 0

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Final Answer :-

The answer is

⇒ P ( - 1 ) = 0

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