Question

3. Find the value of x in each of the following proportions:
(i) 55 : 11 ::x: 6
(ii) 27 :x:: 63: 84
(iii) 51 : 85 :: 57 : x
(iv) x : 92 :: 87: 116
CY​

Answer 1

We know that,
a:b::c:d which is ad=cd

i) 55:11::x:6
So,
11x = 6x55
x = (6x55)/11
x = 330/11
x = 30

(ii) 27:x::63:84
So,
63x = 84x27
x = (84x27)/63
x = 2268/63
x = 36

(iii) 51:85::57:x
So,
51x = 57x85
x = (57x85)/51
x = 4845/51
x = 95

(iv) x:92::87:116
So,
116x = 92x87
x = (92x87)/116
x = 8004/116
x = 69

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