Question

3. Find the volume of co obtained at STP on hex
200 g of 50% pure Caco,
(A) 11.2 litres
(B) 22.4 litres
LEV
(C) 44.8 litres
(D) None of these​

Answer 1

Explanation:

CaCO

3

⇌CaO+CO

2

One mole of calcium carbonate on decomposition gives one mole of carbon dioxide.

The molecular weight of calcium carbonate is 100 g/mol.

10 g calcium carbonate corresponds to 0.1 mol. It on decomposition will give 0.1 mol of carbon dioxide. But limestone is only 90% pure. Hence, 0.09 mol of carbon dioxide will be obtained.

1 mole of carbon dioxide occupies 22.4 L at STP.

Hence, 0.09 mol of carbon dioxide will occupy 0.09×22.4=2.016 L.