Question

3. Find the volume of the cuboid whose dimensions are: (i) length = 26 m, breadth = 14 m and height = 6.5 m (ii) length = 24 m, breadth = 25 m and height = 6 m. how do we get 3600 to the power of 3​

Answer 1

$\; \; \qquad\qquad \large{\pmb{\underline{\underline{\frak{ Part \; (i) }}}}}$

Given :

• Length = 26 m
• Breadth = 14 m
• Height = 6.5 m

$\rule{200pt}{3pt}$

To Find :

• Volume of Cuboid = ?

$\rule{200pt}{3pt}$

Solution :

~ Formula Used :

${\color{cyan}{\bigstar}} \; \; {\underline{\boxed{\red{\sf{ Volume{\small_{(Cuboid)}} = Length \times Breadth \times Height }}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Volume :

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = Length \times Breadth \times Height }}}}$

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = 26 \times 14 \times 6.5 }}}}$

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = 26 \times 91 }}}}$

$\qquad {\color{darkblue}{:\implies{\underline{\boxed{\orange{\sf{Volume = 2366 \; m³ }}}}}}}{\pink{\bigstar}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Therefore :

❝ Volume of the Cuboid is 2366 m³ . ❞

$\\ {\red{\underline{\rule{300pt}{9pt}}}}$

$\; \; \qquad\qquad \large{\pmb{\underline{\underline{\frak{ Part \; (ii) }}}}}$

Given :

• Length = 24 m
• Breadth = 25 m
• Height = 6 m

$\rule{200pt}{3pt}$

To Find :

• Volume of Cuboid = ?

$\rule{200pt}{3pt}$

Solution :

~ Formula Used :

${\color{cyan}{\bigstar}} \; \; {\underline{\boxed{\red{\sf{ Volume{\small_{(Cuboid)}} = Length \times Breadth \times Height }}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Volume :

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = Length \times Breadth \times Height }}}}$

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = 24 \times 25 \times 6 }}}}$

$\; \; {\dashrightarrow{\qquad{\sf{ Volume = 24 \times 150 }}}}$

$\qquad {\color{maroon}{:\implies{\underline{\boxed{\green{\sf{Volume = 3600 \; m³ }}}}}}}{\orange{\bigstar}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Therefore :

❝ Volume of the Cuboid is 3600 m³ . ❞

$\\ {\red{\underline{\rule{300pt}{9pt}}}}$

Answer 2

Answer:

Solution is in the attachment.

hope it helps you!