Question

3) Find the zeroes of the quadratic polynomial and verify the relationship between the zeros and the coefficient X^2 -2x -8​

Answer 1

Answer:

According to the Question

p(x) = x² - 2x - 8

→Splitting the middle term we get :-

= x² - 4x + 2x - 8

= x(x - 4) + 2(x - 4)

⇒(x - 4)(x + 2) = 0

⇒(x - 4) = 0

⇒x = 4

⇒(x + 2) = 0

⇒x = -2

Two zeroes of the polynomial are 4 and -2

★Sum of zeroes = α + β

= 4 + (-2)

= 4 - 2

= 2

★Product of zeroes :-

= α × β

= 4 × -2

= -8

★Put,

ax² + bx + c = 0

a = 1, b = -2 and c = -8

★Sum of Zeroes

α+β=− 1−2= 2

★Product of zeroes :-

α×β= ac

α×β= 1 x −8

Hence verified

Answer 2

Answer:

hey there !

for correct solution of this answer refer to the attached file.......

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hope it helps ......

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