Question

3.Find zeroes of the following
polynomials
1.x² - 5x + 6
2.2x - 3. 3.x+5​

Answer 1

Answer:

1)

$let \: f(x) = {x}^{2} - 5x + 6 \\ = {x}^{2} - 3x - 2x + 6 \\ = x(x - 3) - 2(x - 3) \\ = (x - 3)(x - 2)$

Hence x = 3 or 2

Therefore zeroes of f(x) are 3 and 2.

2)

(2x - 3).(3x - 5)

Hence x = 3/2 or 5/3 are the zeroes of above expression.

Hope this helps :)

Answer 2

Step-by-step explanation:

$1. {x}^{2} - 5x + 6 \\ {x}^{2} - (3 + 2)x + 6 \\ {x}^{2} - 3x - 2x + 6 \\ x(x - 3) - 2(x - 3) \\ (x - 3)(x - 2)$