Question

3. Five year ago, Shakeel was 3 times as old as
Raunak. Ten year later Shakeel would be twice
as old as Raunak. The age of Mr. Shakeel is​

Answer 1

Answer:

Let the age of A be a, and age of B be b

Now, a−5=3(b−5)

a=3b−10 (1)

After 10 years,

a+10=2(b+10)

a=2b+10 (2)

From 1 and 2,

3b−10=2b+10

b=20

And, a=2b+10=2×20+10=50 years

this the age of a=50 years and age of b= 20 years

Answer 2

Answer:

50 years

Step-by-step explanation:

All right let's start,

Raunak age 5 years ago be x,

Shakeel age 5 years ago = 3x

Present age of Raunak = 5 + x

Present age of Shakeel = 3 × (5 + x)

= 15 + 3x

A.T.Q,

Shakeel would be twice as old as Raunak

Now,

2 (x + 15) = 3x + 15

2x + 30 = 3x + 15

2x - 3x = 15 - 30

-x = -15

x = 15

Present age of Raunak = x + 5

15+5

= 20

Present age of Raunak = 20 years

So, Present age of Shakeel =

3x + 5

(3 x 15) + 5

45 + 5

50

So, present age of Shakeel = 50 years

Hope this helps