Question

3. Focal length of a convex mirror is 30 cm.Let an object be placed 15 cm
from the pole of the convex mirror. Find the position of the image.​

Answer 1

Answer:

I think there should be a faster method and this can be determined practically through some experiments.one I know is the no parallax method ,but for the calculation I can remember ,we make use of the mirror equation which is

1/u+1/v= 1/f

Where u is the object distance and v the image distance and f the focal length but according to the real is positive sign convention,the focal length here is negative as convex mirrors produce virtual images and as such have negative focal lengths unlike the concave that produces real and has positive focal lengths . so

1/15+1/v=-1/30

1/v= -1/30–1/15

1/v= -1–2/30

1/v=-3/30=-1/10

v=-10

Take the reciprocal and we have v,the image distance as 10 ,we do not use the negative in further calculation or referring to the value it simply shows the nature if the image as virtual,then to calculate the magnification(m)

m=image distance or height (v)/object distance or height(u)

The image and object heights are relevant in the use of an optical ray box

m=10/15=0.67

This signifies a diminished image because of the magnification less than 1

Explanation:

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Answer 2

Answer:

• The image is real inverted and of same size as that of the object.
• Image formed at 30 cm the same side of object.
• u = -30 cm
• f = -15 cm
• 1/v=1/-30+1/-15
• 1/v=-30/30
• v-1

Explanation:

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