Question

3.
For a given velocity, a projectile has the same range R for two angles of projection if t1 and t2 are the times of flight in the two cases then t1t2 is ​

Answer 1

Explanation:

we get same range for theta, 90-theta

=>t1=2usintheta/g

=>t2=2usin(90-theta)/g=2ucostheta/g