Question

3. For a number series, if t 17 = 54 and t 9 = 30, first p (a)

Find the common difference (d).​

Answer 1

Answer:

Given ,

t17 = 54

=> t+ 16d = 54 -----(eq i)

t9 = 30

=> t+ 8d = 30 -----(eq ii)

Subtracting eq ii from eq i, we have

8d = 24

d = 24

8

d = 3

Therefore, the common difference = 3

Step-by-step explanation:

hope this helps you

Answer 2

Answer:

t 17 = 54

t 17 = a + (n-1) d

54 = a+(17-1)d

54 = a + 16d..(1)

t9 = 30

t9= a + (n-1) d

30 = a+(9-1)d

30=a+8d..(2)

1 - 2

8d = 24

d = 24/8

d = 3

put d = 3 in (2)

30 = a + 8(3)

30 - 24 = a

a = 6

Step-by-step explanation:

a=6

d=3

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