3) For an equation
x = a+bt^2+ct^2,
where x is in metre and t
in second
what will be the dimension of 'b' ?
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Answered by
1
Answer:
Answer
Dimension of a,bt,ct
2
should be equal to x
x=[L]
So, the dimension of bt will be equal to that of 'x'.
bt=[L]
b=
[T]
[L]
b=[LT
−1
]
The dimension of c can be obtained as:
ct
2
=[L]
c=
[T
2
]
[L]
c=[LT
−2
]
Explanation:
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