Physics, asked by sp344583, 15 days ago

3. For the electric circuit given below calculate:
R1 = 5 ohm
R2 = 10 ohm
R3 = 30 ohm
battery 12V
() Equivalent resistance of the Circuit
(ii) Current in each resistor
(iii) Total current drawn from the battery​

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Answers

Answered by SweetLily
4

Given

 \mathtt{ \bull R_1= 5 Ω} \\  \mathtt{\bull R_2= 10 Ω }\\  \mathtt{ \bull R_3= 30Ω }\\   \mathtt{\bull Volt = 12 V}

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To find

  • Equivalent resistance of the Circuit
  • Current in each resistor
  • Total current drawn from the battery

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Concept used

⚘Here the concept of Ohm's Law is used. 3 resistors are arranged in parallel arrangement. The voltage is given. We can find the total current and current in individual series by V=IR.

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Solution

Equivalent resistance of the circuit

➶Equivalent resistance in parallel is given as

 \sf{\dfrac{1}{R_eq}= \dfrac{1}{R_1}+ \dfrac{1}{R_2}+ \dfrac{1}{R_3}....+ \dfrac{1}{R_n}}

substitute the values

 \sf{\frac{1}{R_eq}= \frac{1}{5}+ \frac{1}{10}+ \frac{1}{30}}

 \sf{\frac{1}{R_eq}= \frac{6+3+1}{30}}

 \sf{\frac{1}{R_eq}= \frac{10}{30}}

 \sf{\frac{1}{R_eq}= \frac{1}{3}}

 \bold{ \red{R_eq= 3Ω}}

so the equivalent resistance is the circuit is 3Ω

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Current in each resistor

Using V=IR [ohm's Law]

We know that the voltage in the parallel arrangement is same and voltage in series arrangement is different. so we will take same voltage throughout the calculations.

 \sf{ \implies current  \: in \:  resistor = \dfrac{V}{R}}

 \sf{»current  \: in \:  5 \: Ω \:  resistor = \frac{12}{5}}

 \sf{» \green{current  \: in  \: 5 \: Ω  \: resistor =2.4 \:  Ampere}}

 \sf{»Current \:  in  \: 10 \: Ω \:  resistor=  \frac{12}{10}}

 \sf{» \green{Current  \: in \:  10 \: Ω \:  resistor= 1.2  \: Ampere}}

 \sf{» current  \: in  \: 30 \: Ω \: resistor =  \frac{12}{30}}

 \sf{» \green{current  \: in \:  30 \: Ω  \: resistor= 0.4 \:  Ampere}}

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Total current drawn from the battery

Using V= IR [ohm's Law]

Now we will find the total current in the circuit by dividing the voltage by total resistance.

V= IR

 \sf{➛I = \frac{V}{R}} \\ \\ \sf{➛I =  \frac{12}{3}}

 \sf{➛ \red{I = 4  \: Ampere}}

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Verification

The sum of current in each resistor should be equal to the total current in circuit.

  \sf{➛ \pink{2.4 +1.2+0.4 = 4  \: Ampere}}

◍ hence verified..!

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