Chemistry, asked by devanshgupta04, 6 months ago

3
For the exothermic formation of sulphur trioxide from sulphur dioxide and oxygen in the
phase
2502(9) + O2(9) 280, (9)
K = 40.5 atm-' at 900 K and AH = - 198 kJ.
Write the expression for the equilibrium constant (K) for the reaction.
(ū) At room temperature (-300 K), will Ko be greater than less than or equal to ka 9000
(ii) How will the equilibrium be affected if the volume of the vessel containing three gases
is reduced, keeping the temperature constant?
(iv) What is the effect of adding 1 mole of He(9) to a flask containing SO, O, and SO,
equilibrium at constant temperature​

Answers

Answered by pari2008chitra61
0

Answer:

At a given temperature, the equilibrium constant for the reactions: NO(g) + 2 0,(9) NO2 (9) and 2 NO, () 2 NO (g) + O2(g) are K, and K, respectively. If K, is 4...

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