Question

3) For the given quadratic equation 3x2 - 15x + 3 = 0, then find the value of
$\alpha + \beta$

a -15
b. 5
C 1
d. 5​

Answer 1

$\huge \mathfrak \red {answer}$

$\large \bf \green {given :} \sf \: quadratic \: equation \: = 3 {x }^{2} - 15x + 3 = 0$

$\large \bf \green{to \: find : } \sf \: sum \: of \: zeros \: ie \: \alpha + \beta$

$\sf \: as \: we \: know \: \boxed{ \alpha + \beta = \frac{ - b}{a} }$

$\sf \: where \: b = - 15 \: and \: a = 3$

$\sf \: now \: substituting \: value \: of \: a \: and \: b \: is \: given \: formul$

$\sf \: so \: \alpha + \beta = \frac{ - ( - 15)}{ + 3} \\ \\ \sf \alpha + \beta = \frac{15}{3} \\ \\ \sf \: \alpha + \beta = 5$

$\bf \: so \: value \: of \: \alpha + \beta = 5$

hope it helps you

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