Question

3. For the reaction: CaCO3(s) = Cao(s) + CO2(g), Kp is equal to
(1) Kc
(2) KcRT
(3) Kc(RT)2
(4) Kc(RT)​

Answer 1

Explanation:

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Answer 2

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Given, K

P

=1 atm=P

CO2

V=10 liters

Temperature=927+273=1200 K

m=20 g

⟹PV=nRT

⟹(1)(10)=(n)(0.0821)(1200)

⟹n=0.1moles

0.1 moles of CO2 is produced.

So, 0.1 moles of CaCO3 is consumed, i.e.,10 g of CaCO3 is consumed and 50% of CaCO3

is remaining.