Question

3. For what values of K, the equation x+y+z=1, 2x+y +4z=K, 4x+y + 10z =K² have infinite no
of solution Hence find its solution.​

Answer 1

Answer:

K = 2

Step-by-step explanation:

X+Y+Z = 1

2X+Y+4Z = K

4X + Y + 10Z = K²

2X+Y+4Z - ( X+Y+Z) = K - 1

=> X + 3Z = K - 1

4X + Y + 10Z - (2X+Y+4Z) = K² - K

=> 2X + 6Z = K (K - 1)

=> 2(X + 3Z) = K (K - 1)

=> 2(K - 1) = K (K - 1)

cancelling K - 1 from both Sides

=> 2 = K

K = 2

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