3 Friends went to a shop and purchased 3 toys. Each person paid Rs.10 which is the cost of one toy. So, they paid Rs.30 i.e. total amount. Shop owner gave a discount of Rs.5 on the total purchase of 3 toys for Rs.30. Then, among Rs.5, Each person has taken Rs.1 and remaining Rs.2 given to the beggar beside the shop. Now, the effective amount paid by each person is Rs.9 and the amount given to the beggar is Rs.2. So, total effective amount paid is 9*3 = 27 and the amount given to beggar is Rs.2, thus the total is Rs.29. Where has the other Rs.1 gone from the original Rs.30 ?
Answers
Answer:
logic is not known as of now
Step-by-step explanation:
thanks for the points
Given:
Three friends went to a shop and purchased 3 toys. Each of them has paid Rs. 10. The total amount paid by them is Rs. 30. The owner has given a discount of Rs. 5. Each of the friends takes Rs. 1 and gives the remaining 2 rupees to the beggar. Each of them has effectively paid Rs. 9 each, with a total of 27 rupees + 2 rupees to the beggar equals 29 rupees. But the total is 30 rupees.
To Find:
The remaining 1 rupee (OR) the error in the above calculation is?
Solution:
1. Initially each of them has paid Rs. 10 each.
=> The total amount paid by three friends = 10 x 3 = Rs. 30.
2. As the shopkeeper gives a discount of 5 rupees,
=> Total amount paid by three friends = 25 rupees,
=> Net effective amount paid by each friend = 8.33 rupees.
3. The three friends decide to take one rupee each from the discount amount and donate the remaining two rupees to the beggar.
=> Hence the total calculation of 30 rupees is = 8.33 x 3 ( for each toy ) + 1 x 3 ( friends sharing among the discount amount ) + 2 ( amount given to the beggar ).
=> 25 + 3 + 2 = 30 rupees.
=> Hence, the given calculation in the question is incorrect and the correct calculation is mentioned above.
Therefore, there is no loss of money as the calculation is done incorrectly.