Question

3.
From the figure, AB = CD and AB || to CD then,
show that ∆AOB=∆COD​

Answer 1

Step-by-step explanation:

Given, AB || CD and AB = CD

As line AB is parallel to CD, by the properties of parallel lines,  ABO should be equal to  OCD.

Therefore,

ABO =  OCD ----: ( 1 )

Also,  AOB is vertically opposite to  COD, and we know that vertically opposite angles are always equal.

Therefore,

AOB=  COD ----: ( 2 )

Now,

= > AB = CD ( Given in the question )

= >  ABO =  OCD ( From 1 )

= >  AOB =  COD.

Thus,

AOB  DOC, by ASA.

And, hence AO = DO, also BO = CO.

Hence proved.

please mark my answer as a brainlist