Question

3. From the sum of 2y+3yz, _Y2_y2–2Z and yz+27
subtract the sum of3y_z_andy
tyz+z?.
1)-y2+2yz
2) y2+2yz
3) y2-2yz
4)-(y2+2yz)​

Answer 1

Answer:

sum is to big

Step-by-step explanation:

Answer 2

Answer:

$- 3yz + z + 4y + {y}^{2}$

Step-by-step explanation:

We have to subtract sum of 2y +3yz, -y^2- 2y -2z and yz +27 from the sum of 3y-z and y

$yz + 27 + 3y - z \: + y \\ yz + 27 + 4y - z \\ now \: 2y + 3yz + ( - {y}^{2} - 2y - 2z) + yz + 27 \\ 2y + 3yz - {y}^{2} - 2y - 2z + yz + 27 \\ 4yz - {y}^{2} - 2z + 27 \\ yz + 27 + 4y - z - (4yz - {y}^{2} - 2z + 27) \\ yz + 27 + 4y - z - 4yz + {y}^{2} + 2z - 27 \\ - 3yz + z + 4y + {y}^{2}$