3 g of a salt of molecular weight 30 is dissolved in 250 g of water. The molality of the solution is ............... .
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Molality = moles of solute / mass of solvent
First find moles of salt
n = m / M = 3 / 30 = 0.1moles
Mass of solvent = 250g = 0.25kg
Now put in formula
= 0.1 / 0.25
= 0.4 moles/kg
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