Question

3. Given, root2 = 1.414 and root 6 = 2.449, find the value of
1 by root 3 minus root 2 minus 1 to 3 places of decimal​

Answer 1

Answer:

The required answer is $\sf -1.464$

Step-by-step explanation:

Given Data -

√2 = 1.414 & √6 = 2.449.

To Find -

The value of $\dfrac{1}{\sqrt{3}-\sqrt{2}-1}$

Solution -

• First step -

Find the value of √3

So,

$\sf\\ \\\implies \sqrt{6}=2.449\\ \\ \implies \sqrt{2}\times\sqrt{3}=2.449\\ \\\implies 1.414\times\sqrt{3}=2.449\\ \\\implies \sqrt{3}=\dfrac{2.449}{1.414}\\ \\ \implies\bf \sqrt{3}=1.731$

∴ The value of √3 is 1.731.

• Second Step -

Put all the values in the expression,

So,

$\sf\\ \\\implies \dfrac{1}{\sqrt{3}-\sqrt{2}-1}\\ \\ \implies \dfrac{1}{1.731-1.414-1}\\ \\ \implies\dfrac{1}{-0.683}\\ \\ \implies -1.4641$

$\therefore \bf \dfrac{1}{\sqrt{3}-\sqrt{2}-1}=-1.464$

Answer 2

Answer:

For showing full answer click on photo .