3 gm of h2 reacts with 29g of oxygen to yield water. Which one is the limiting reagent
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heya....
First write the chemical equation.
2H₂ + O₂ -----> 2H₂O
For 2H₂ - 2 x 2 = 4 g
O₂ - 32 g
2H₂O - 2 x 18 = 36 g
Now, we have to determine the limiting reagent.
4 g of H₂ reacts with 32 g of O₂
1 g of H₂ reacts with 32/4 g of O₂
3 g of H₂ reacts with 32/4 x 3 = 24 g of O₂
But according to the question, 29 g of O₂ is present.
So, the limiting reactant is hydrogen.
tysm..#gozmit
First write the chemical equation.
2H₂ + O₂ -----> 2H₂O
For 2H₂ - 2 x 2 = 4 g
O₂ - 32 g
2H₂O - 2 x 18 = 36 g
Now, we have to determine the limiting reagent.
4 g of H₂ reacts with 32 g of O₂
1 g of H₂ reacts with 32/4 g of O₂
3 g of H₂ reacts with 32/4 x 3 = 24 g of O₂
But according to the question, 29 g of O₂ is present.
So, the limiting reactant is hydrogen.
tysm..#gozmit
dineshgupta2174:
Thank you soo much for ur help. I was very much confused about this question.
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