Question

3 guaves and 4 orange cost Rs 29.similarly, 1 guave and 8 orange cost Rs 43 .now find out cost of 1 orange.

Answer 1

Explanation:

let cost of 1 guava be x and cost of 1 orange be y

3x+4y=29. (1)

x+8y=43

3x +24y=129. (2)

subtract (1) from (2)

20y=100

y=5

cost of 1 orange is Rs 5

Answer 2

Answer:

Rs5

Explanation:

let the cost of one guava be x

and the cost of one Orange be y

so,

$3 x + 4y = 29 \: \: \: \: \: \: eq1$

and,

$1x + 8y = 43 \\ \\ x = 43 - 8y \: \: \: \: \: \: \: \: \: \: \: \: eq2$

put the value of x in eq1

$3x + 4y = 29 \\ \\ 3(43 - 8y) + 4y = 29 \\ \\ 129 - 24y + 4y = 29 \\ \\ - 20y = 29 - 129 \\ \\ - 20y = - 100 \\ \\ y = 100 \div 20 \\ \\ y = 5$

put the value of y in eq2

$x = 43 - 8y \\ \\ x = 43 - 8 \times 5 \\ \\ x = 43 - 40 \\ \\ x = 3$

cost of one guava = Rs3

and the cost of one Orange = Rs 5