Question

3) How many atoms of carbon are present in 65
of Oxalic acid (HC204)?​

Answer 1

Answer:

8.6 × 10^23 atoms

Explanation:

First of all u have written wrong formula of oxalic acid

Correct formula is H2C2O4

Now atomic wt of Oxalic acid is 90 gm

so No of moles of oxalic acid in 65 gm = 65/90

now 1 mole of oxalic acid have 2 mole of carbon atom

so 65/90 moles contain 13/9 mole of carbon

13/9 moles means 8.6 × 10^23 atoms of carbon