3. How many bricks each 25 cm long, 16 cm wide and 7.5 cm thick, will be required to build a terrace 5 m long, 3 m broad and 80 cm high?
Answers
ANSWER
Step-by-step explanation
BRICK
Length = 25cm
Width = 16cm
Thick = 7.5cm
Area of brick = l×b×t
= 25×16×7.5
= 3000 cm^2
TERRACE
Length = 5m = 500cm
Breadth = 3m = 300cm
Height = 80cm
Area of terrace = l×b×h
= 500×300×80
= 12000000cm^2
So,
Number of bricks required to built the terrace
= Area of terrace/ area of brick
= 12000000 / 3000
= 4000
Hence, 4000 bricks required to built the terrace.
Given :
For Brick
- Length of the Brick → 25 cm
- Breadth of the Brick → 16 cm
- Height of the Brick → 7.5 cm
For Terrace :
- Length of the Terrace → 5 m Or 500 cm
- Breadth of the Terrace → 3m or 300 cm
- Height of the Terrace → 80 cm
Have to Find :
- How many bricks required to build the terrace?
Formula related to Cuboid :
- {TSA - 2(lb + bh + hl)}
- {CSA - 2(l + b)h}
- {Volume - l × b × h}
Where,
" l " → Length
" b " → Breadth
" h " → Height
Solution :-
For brick -
As from the given we know the dimension,
therefore,
finding the volume of brick
Length (l) = 25 cm
Breadth (b) = 16 cm
Thickness (h) = 7.5 cm
Volume of the brick -> {Volume - l × b × h}
Where,
" l " → Length
" b " → Breadth
" h " → Height
Substituting the values in it, we get
25 cm × 16 cm × 7.5 cm
3000 cm³
________________________
For terrace
From the given we know the dimension of the terrace-
Length (l) = 5 m = 500 cm
Breadth (b) = 3 m = 300 cm
Height (h) = 80 cm
Now , the volume of the terrace -{Volume - l × b × h}
Where,
" l " → Length
" b " → Breadth
" h " → Height
Substituting the values in it, we get
500 cm × 300 cm × 80 cm
12000000 cm³
_______________________
Hence , For number of bricks required to build the terrace, we have to subtract the volume of one brick from the volume of terrace.
Volume of terrace / volume of one brick
12000000 cm³/3000 cm³
4000.
Thus, the number of bricks required is 4000