Question

(3) How many grams of HCl reacts with 8.7 gram of MnO2?
MnO2 + 4HCI
MnCl2 + 2H20
(atomic mass of Mn = 55, 0 = 16, CI= 35.5)
a) 1.46 g
b) 14.6 g c) 7.3 g d) 3.65 g​

Answer 1

Answer:

hi

Explanation:

The balanced chemical equation is as given below:

MnO

2

+4HCl⟶MnCl

2

+2H

2

O+Cl

2

1mol4mol

0.86mol 48.2g=1.32mol

HCl required by 0.86 mol MnO

2

=3.44mol

but HCl taken =1.32mol

Thus, HCl is the limiting reactant.

Thus, Cl

2

formed=

4

1

×1.32

=0.33molCl

2

=23.43g

Hence, 23 g of chlorine will be produced.

correct option A