Question

3.
How many moles are present in each of the following samples?
30 g of mes
b. 8.85 kg of Co,
7.5 x100 molecules of C.H.​

Answer 1

answer:

b) 8.85 kg of CO

mole= given mass/ molar mass

= 8850gm/ 28u

= 4425/ 14 moles

c) 7.5 ×100 molecules of CH

mole = no. of molecules/ NA

= 7.5 ×100/6.022×10^23

= 7.5×10^21/6.022

Mark me as brilliant