Question

3. How many three-digit numbers are divisible by 7
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Answer 1

Answer:

A.P.= 105,112,119--------------------994.

Tn=994, a=105, D=7, n=?

Tn = [a + (n-1)D]

994 = [105 + (n-1)7]

994-105 = (n-1)7

889/7 = (n-1)

127 = n-1

$\boxed {n = 128}$

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Answer 2

♡[Answer]♡

The first 3-digit number which is divisible by 7 is 105.

The last 3-digit number which is divisible by 7 is 994.

The list of 3-digit numbers divisible by 7 are 105,112,119.................994which forms an A.P.

Consider a formula

T(n) = a+(n-1)d

Where a = 105

d = 7

T(n) = 994

994 = 105+(n-1)7

889 = 7n-7

7n = 896

n = 128

Therefore, there are 128-3 digits numbers which is divisible by 7.

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