Question

3. How many tiles are required to cover a floor of length 6 m and breadth 4 m, if the area
covered by each tile is 400 sq. cm ?​

Answer 1

Area of the floor =6×4=24m

24m=24000cm

So number tiles required = 24000÷400=60

so 60 tiles are required to cover the floor

Answer 2

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Area of the floor = length × breadth

$= 6 \times 4 \\ \\ = 24 {m}^{2} \\ \\ = 240000cm$

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No of tiles required to cover the floor

$= \frac{area \: of \: the \: floor \: }{area \: of \: one \: tile} \\ \\ = \frac{240000}{400} \\ \\ = \frac{2400}{4} \\ \\ = 600$

THEREFORE 600 TILES ARE REQUIRED TO COVER THE FLOOR

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