Question

3) How many times does the digit 1 occur in a two-digit number?

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Answer 1

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It occurs 19 times, in 18 numbers.

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Answer 2

Answer:

• well
• as we have two digit number let’s make two boxes two boxes [ ][].we can feel the first box with (1,2,3,4,5,6,7,8,9)and the second with(0,1,2,3,4,5,6,7,8,9) so total no of two digit number will be 9*10=90.
• now we have to calculate total no of two digit no without one. again take two boxes [ ][ ] now we can the first box with (2,3,4,5,6,7,8,9) and second with (0,2,3,4,5,6,7,8,9) so total no of two digit no without one will be 8*9=72.
• so now total no of time digit one occur in two digit no=total no of two digit no-total no of two digit number without one.
• total no of time digit one occur in two digit no=90–72=18
• so total no of two digit number containing one is 18.
• and digit one occur 19 times. as in 11 there are two 1.

Step-by-step explanation:

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