Question

3. How much Geetanjali was to repay, if she had to settle a loan of 16,000 at compound interest after 3 years, interest being payable yearly?​

Answer 1

Answer:

7.8000000 is the answer I think

Answer 2

Answer:

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3)

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)A=16000(1.1×1.12×1.15)

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)A=16000(1.1×1.12×1.15) A=16000×1.4168

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)A=16000(1.1×1.12×1.15) A=16000×1.4168A=22668.8

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)A=16000(1.1×1.12×1.15) A=16000×1.4168A=22668.8Amountwillbe22668.8

Whenratesofdifferentyearisgivenformulatocalculateamountis A=P(1+100R1)(1+100R2)(1+100R3) Givenprincipalis16000A=16000(1+10010)(1+10012)(1+10015)A=16000(1.1×1.12×1.15) A=16000×1.4168A=22668.8Amountwillbe22668.8∴  Compound interest accrued will   be =22,668.80−Rs.16,000=Rs.6,668.80