Question

(3+i√5)(3-i√5)/(√3+√2i)-(√3-i√2) express in a+ib form

Answer 1

(3+i√5)(3-i√5)/(√3+√2i)-(√3-i√2) = 14/(√3+√2i)-(√3-i√2)

{ (a-b)(a+b) = a^2 - b^2)}

= 9/(√3+√2i) = 9/5(√3+√2i)