Question

3. (i) If a+b+c=13 and ab+bc+ca =50 then find the value of a2 +62 +c2 ​

Answer 1

Answer:

Step-by-step explanation:

a²+b²+c²=(a+b+c)²+2(ab+bc+ca)

              =13²+2×50

              =169+100

              =269

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Answer 2

Answer:a² +  b² + c² = 69

Step-by-step explanation: Now we know that a + b + c = 13 , ab+bc+ca =50

and we have to find  a² +b² +c² ​

First we will square both sides

(a + b + c )² = 13²

a² +  b² + c² + 2ab + 2bc + 2ca = 169

Now lets take 2 as a common

a² +  b² + c² + 2(ab + bc + ca) = 169

Now we know that ab+bc+ca = 50

a² +  b² + c² + 2(50) = 169

a² +  b² + c² + 100 = 169

a² +  b² + c² = 169 - 100

a² +  b² + c² = 69

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