3..(i) समीकरण 2x -3y =13 तथा 7x-2y = 20 को हल कीजिए
और y =m.x + 7 के लिए m का मान ज्ञात कीजिए।
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2x-3y=13
7x-2y =20
multiple eq1 by 7 and eq2 by 2
14x-21y= 91
14x-4y=40
by subtracting
14x - 21y =91
14x -4y = 40
- +. - (sign change
we get-17y = 51
y =51/-17=-3
2x-3y=13
2x-3×(-3)=13
2x+9=13
2x = 4
x =2
y = mx+7
-3 = m×2+7
-3-7=2m
-10 = 2m
m=-5
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